Question

X square + 2 x - 5 equals to 0 ​

Answer 1

x = -1 ± √6

Explanation:

`x^(2) +2x - 5 = 0`

Lets use the quadratic formula →
`x = \frac{-b + \sqrt{b^(2) - 4ac} }{2a} \:or \frac{-b - \sqrt{b^(2)- 4ac } }{2a}`

So ,

`x = \frac{(-2) + \sqrt{(2)^(2) - (4*1*-5) } }{2*1} \:or \frac{(-2) - \sqrt{(2)^(2) - (4*1*-5) }}{2*1}`

`=> x = (-2 + √(24) )/(2) \:or (-2-√(24) )/(2)`

`=> x = (-2 + 2√(6) )/(2) \:or (-2 - 2√(6) )/(2)`

Lets take 2 common from numerator.

`=> x = (2(-1 + √(6)) )/(2) \:or (2(-1-√(6)) )/(2)`

Cancelling 2 from numerator & denominator gives

`x = (-1+√(6) ) \: or (-1 - √(6) )`