Question

a box has a momentum of 1.30 kg*m/s to the right. a 12.8 N force pushes it to the right for 0.218 s. what is the final momentum of the box. PLEASE HELP

Answer 1

4.09

Step-by-step explanation:

Correct on Acellus

Answer 2

4.09 kgm/s

Step-by-step explanation:

Concept tested: Second Newton's law of motion

So what does the second Newton's law of motion state?

• According to the second Newton's law of motion, the resultant force and the rate of change of momentum are directly proportional.

• That is;
  `F=((mVf-mVo))/(t)`, where, mVf is the final momentum and mVo is the initial momentum.

In this case;

• Force = 12.8 N
• Initial momentum, mVo = 1.3 kgm/s
• Time, t = 0.218 seconds

Therefore; replacing the values of the variables in the formula;

we get;

`12.8N=((mVf-1.3kgm/s))/(0.218s)`

`(12.8N)(0.218s)=(mVf-1.3kgm/s)`

`2.7904+1.3=mVf`

Solving for final momentum;

`mVf =4.0904 kgm/s`

= 4.09 kgm/s

Therefore, the final momentum of the box is 4.09 kgm/s