Answer:
Complete ionic equation: Na⁺(aq) Cl⁻(aq) + Mg(OH)₂(s) → Na⁺(aq) OH-(aq) +Mg²⁺(aq) 2Cl⁻(aq)
Net ionic equation: Mg(OH)₂(s) → OH-(aq) +Mg²⁺(aq)
Step-by-step explanation:
Concept tested: Writing ionic equations
In this case;
- We are given sodium chloride and magnesium hydroxide as the reactants;
- Sodium chloride reacts with magnesium hydroxide to form sodium hydroxide and magnesium chloride.
- The equation for the reaction is;
NaCl(aq) + Mg(OH)₂(s) → NaOH(aq) + MgCl₂(aq)
We need to write the ionic equation showing ions in the ionic compound;
- Therefore, the complete ionic equations
Na⁺(aq) Cl⁻(aq) + Mg(OH)₂(s) → Na⁺(aq) OH-(aq) +Mg²⁺(aq) 2Cl⁻(aq)
To write the net ionic equation we identify the spectator ions.
- Net ionic equations are equation only showing the ions involved in the reaction and omits the spectator ions.
- Spectator ions are ions that do not change their state during the reaction.
- In this case; the spectator ions are; Na⁺ and Cl⁻ as they remained in aqueous state before and after the reaction.
- Therefore, the net ionic equation for the reaction is;
Mg(OH)₂(s) → OH-(aq) +Mg²⁺(aq)