A) Starting from rest, we have the entire cycle determined by 0.8s.
If we assume a constant movement, half of that time is when it reaches the highest point, that is, in 0.4s.
The distance as a function of speed and acceleration is given by,

At the initial point the speed is zero and the acceleration is equivalent to gravity.


B) When returning to the ground, the final speed is zero. Therefore, the equation that relates velocity to acceleration is given by,


