For this case we have that by definition, the equation of a line of the slope-intersection form is given by:
![y = mx + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/fc4cgm6covys37zv2opmmp9ps4jxyjepvh.png)
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have to, if two lines are parallel then their slopes are equal.
We have the following equation of the line:
![2x + 4y = 5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ljfftst8hv1skcgf4c3j9wwp2lgxvag6uf.png)
We manipulate algebraically to convert to the slope-intersection form:
![4y = -2x + 5\\y = - \frac {2} {4} x + \frac {5} {4}\\y = - \frac {1} {2} x + \frac {5} {4}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/szg3b9x8shkng3va2xrzalvmzprw47m5g6.png)
Thus,
, then a parallel line will have a slope
![m_ {2} = - \frac {1} {2}.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1lyhligtiti5k0keku0b3ibd00s2pohfc4.png)
Answer:
The slope is:
![m_ {2} = - \frac {1} {2}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tgs5qdkiumhqtg959w92lvvlmb28opg871.png)