Question

Joe pushes down the length of the handle of an 11.6 kg lawn spreader. The handle makes an angle of 46.2 ◦ with the horizontal. Joe wishes to accelerate the spreader from rest to 1.37 m/s in 1.6 s. What force must Joe apply to the handle? Answer in units of N.

Answer 1

F = 9.93N

Step-by-step explanation:

We start the development of the exercise through the second law of Newton.

The second law tells us that

`F = m a`

But we also understand that Acceleration is the change in speed in a given time, this is

`a = \frac {\Delta V} {\Delta t}`

Replacing,

`F = m \frac {\Delta V} {\Delta t}`

Our values are,

`m = 11.6Kg\\\Delta V = 1.37m / s\\\Delta t = 1.6s`

Substituting

`F = 11.6 * \frac {1.37} {1.6}`

`F = 9.93N`

We can conclude that the force Joe must apply in the handle is 9.93N