Question

1. Write an equation in slope-intercept form of the line that passes through the given point and is parallel to

the graph of the given equation.
(2,-2) ;y=-x-2
y=-2х
y = 2х
y= 1/2x
y=-x

Answer 1

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

`y = mx + b`

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have to, if two lines are parallel then their slopes are equal.

If we have
`y = -x-2`with slope
`m_ {1} = - 1`, then a parallel line will have slope
`m_ {2} = - 1.`

Thus, the equation of the parallel line is of the form:

`y = -x + b`

We substitute the given point and find "b":

`-2 = - (2) + b\\-2 = -2 + b\\-2 + 2 = b\\b = 0`

Finally, the equation is:

`y = -x`

Answer:

`y = -x`