186k views
5 votes
1. Write an equation in slope-intercept form of the line that passes through the given point and is parallel to

the graph of the given equation.
(2,-2) ;y=-x-2
y=-2х
y = 2х
y= 1/2x
y=-x

User OrionMelt
by
9.2k points

1 Answer

4 votes

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:


y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have to, if two lines are parallel then their slopes are equal.

If we have
y = -x-2with slope
m_ {1} = - 1, then a parallel line will have slope
m_ {2} = - 1.

Thus, the equation of the parallel line is of the form:


y = -x + b

We substitute the given point and find "b":


-2 = - (2) + b\\-2 = -2 + b\\-2 + 2 = b\\b = 0

Finally, the equation is:


y = -x

Answer:


y = -x

User Kwcto
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories