The explicit formula is a(n) = 15(n – 10)
Solution:
Given, a term a(19) = 135 and common difference d = 15
We have to find the explicit formula.
Now, we know that, a(n) = a + (n – 1)d where a(n) is nth term, a is first term, d is common difference,
So, for a(19)
![\begin{array}{l}{\rightarrow a(19)=a+(19-1) 15} \\\\ {\rightarrow 135=a+18 * 15} \\\\ {\rightarrow a=135-270} \\\\ {\rightarrow a=-135}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/taj2n52oz0zafzatz6gzbf06uvkl1yvvaq.png)
Now, we know that, an explicit formula is an expression for finding the nth term,
So, in our problem, expression for finding nth term is a + (n – 1)d
![\begin{array}{l}{\rightarrow-135+(n-1) 15} \\\\ {\rightarrow-135+15 n-15} \\\\ {\rightarrow 15 n-150} \\\\ {\rightarrow 15(n-10)}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7irwefon8soy789gsg41z81ta2zewjd8mg.png)
Hence, the explicit formula is a(n) = 15(n – 10).