Question

Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x).

Answer 1

its c

Explanation:

i took the test

Answer 2

For this case we have the following functions:

`k (x) = 2x ^ 2-7\\p (x) = x-4`

We must find
`(k_ {0} p) (x)`. By definition of compound functions we have to:

`(k_ {0} p) (x) = k (p (x))`

So:

Taking into account that:

`(a-b) ^ 2 = a ^ 2-2ab + b ^ 2`

Different signs are subtracted and the major sign is placed.

`k (p (x)) = 2 (x-4) ^ 2-7 = 2 (x ^ 2-2 (x) (4) + 4 ^ 2) -7 = 2 (x ^ 2-8x + 16) -7 = 2x ^ 2-16x + 32-7 = 2x ^ 2-16x + 25`

Finally we have to:

`(k_ {o} p) (x) = 2x ^ 2-16x + 25`

Answer:

`(k_ {o} p) (x) = 2x ^ 2-16x + 25`