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1 vote
What is the [OH-] in a solution
with a POH of 7.86?
[OH-] = [?] x 10!?)

2 Answers

5 votes

Answer:

Coefficient: 1.38 Exponent:-8

Step-by-step explanation:

Acellus

User Alexander Samoylov
by
5.5k points
5 votes

Answer:

1.380 × 10^-8 M

Step-by-step explanation:

The pH is the measure of alkalinity or acidity of a substance.

It is the negative logarithm of H+ ions concentration [H+].

pH = -log[H+]

pOH on the other hand is negative logarith of OH- concentration [OH-].

pOH = -log[OH-]

In this case;

pOH = 7.86

We can calculate the [OH-]

pOH = -log[OH-]

But, pOH = 7.86

pOH = -log[OH-]

-log[OH-] = 7.86

[OH-] = Antilog -7.86

= 1.380 × 10^-8 M

Therefore, [OH-] is 1.380 × 10^-8 M

User Luxspes
by
5.8k points