Question

Given the equation square root of quantity 3x plus 4 end quantity equals 5, solve for x and identify if it is an extraneous solution.

7; solution is not extraneous

7; solution is extraneous

four thirds; solution is not extraneous

four thirds; solution is extraneous

Answer 1

7; solution is not extraneous

Step-by-step explanation:

we have

Solve for x

squared both sides

subtract 4 both sides

Divide by 3 both sides

Verify

Substitute the value of x in the original equation

----> is true

therefore

The value of x=7 is a solution, Is not a extraneous

Answer 2

7; solution is not extraneous

Explanation:

we have

`√(3x+4)=5`

Solve for x

squared both sides

`(√(3x+4))^2=5^2`

`3x+4=25`

subtract 4 both sides

`3x=25-4`

`3x=21`

Divide by 3 both sides

`x=7`

Verify

Substitute the value of x in the original equation

`√(3(7)+4)=5`

`√(21+4)=5`

`√(25)=5`

`5=5` ----> is true

therefore

The value of x=7 is a solution, Is not a extraneous