Question

You shake a bottle of soda and take off the cap. If the soda shoots out of the

bottle with a velocity of 15 m/s, how high will it go?
A. 11.5 m
B. 8.3 m
C. 10.6 m
D. 12.7 m

Answer 1

A. 11.5 m

Step-by-step explanation:

Given,

The initial velocity of the soda cap, u = 15 m/s

The soda bottle cap is projected vertically upwards,

Hence, the angle formed with the ground, Ф = 90°

The maximum height of the projectile is given by the formula,

`h_(max) =(u^(2)sin^(2)\phi)/(2g)`

Substituting the given values in the above equation

`h_(max) =(15^(2)sin^(2)90)/(2X9.8)`

= 11.5 m

Hence, the maximum height of the cap is h = 11.5 m