Answer:
Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below. Please see the file attached below to know the diagram.
Step-by-step explanation:
There is the following solution that satisfies all requirements indicated on statement:
Connecting the 4-ohm and 12-ohm in parallel and followed by the 3-ohm resistor in series. A scheme of the configuration is attached below.
![R = ((12\,\Omega)\cdot (4\,\Omega))/(12\,\Omega+4\,\Omega)+3\,\Omega](https://img.qammunity.org/2022/formulas/physics/high-school/p6sy7aedkewalfg0e5iot02umctck7nx3o.png)
![R = 6\,\Omega](https://img.qammunity.org/2022/formulas/physics/high-school/r04ph1dxotgohji3kyzrhyu1e26my19p1s.png)
Which observes all design requirements.