Answer:
V = 4.7 m/s
Step-by-step explanation:
Given,
The diameter of Mar's moon, Deimos, D = 12 Km
Radius, R = D/ 2 = 12 /2 = 6 Km
= 6000 m
The mass of the moon, m = 2 x 10¹⁵ Kg
in order to catch a baseball after orbiting the moon, it should be thrown with a velocity equal to the orbital velocity at that surface.
The orbital velocity at surface is given by,
V = √(GM/R) m/s
Substituting the given values in the above equation,
V = √(6.673 x 10⁻¹¹ x 2 x 10¹⁵ / 6000)
= 4.7 m/s
Hence, the baseball should be thrown with a velocity that would return after orbiting is, V = 4.7 m/s