Question

Two coils are at fixed locations. When coil 1 has no current and the current in coil 2 increases at the rate 17.8 A/s, the emf in coil 1 is 27.1 mV. (a) What is their mutual inductance? (b) When coil 2 has no current and coil 1 has a current of 4.00 A, what is the flux linkage in coil 2?

Answer 1

Part a)

`M = 1.52 mH`

Part b)

`\phi = 6.09 * 10^(-3) Tm^2`

Step-by-step explanation:

Part a)

As we know by Faraday's law

`EMF = M (di)/(dt)`

so we will have

`EMF = 27.1 mV`

`EMF = 27.1 * 10^(-3) V`

`(di)/(dt) = 17.8 A/s`

so we will have

`M = (V)/((di)/(dt))`

`M = (27.1 * 10^(-3))/(17.8)`

`M = 1.52 mH`

Part b)

As we know by Lenz law

`\phi = Mi`

so we have

`\phi = (1.52 * 10^(-3))(4)`

`\phi = 6.09 * 10^(-3) Tm^2`