Question

A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C. Calculate the initial temperature of the piece of copper. Assume that all heat transfer occurs between the copper and the water.

Answer 1

The answer to your question is: Initial temperature of copper = 67.1°C

Step-by-step explanation:

Data

mass Copper = 248 g

volume Water = 390 ml

T1 water = 22.6°C

T2 = 39.9°C

T1 copper = ?

Specific heat water = 1 cal/g°C

Specific heat copper = 0.092 cal/g°C

Formula copper water

Heat is negative for copper because it releases heat

- mCp(T2 - T1) = mCp(T2 - T1)

- (248)(39.9 - T1) = 390 (1)((39.9 - 22.6) Substitution

-9895.2 + 248T1 = 390(17.3) Simplification

-9895.2 + 248T1 = 6747

248 T1 = 6747 + 9895.2

248 T1 = 16642.2

T1 = 16642.2 / 248

T1 = 67.1 °C Result