Answer:
The answer is that the vertex is: (1, 0)
Explanation:
Use the "Completing the Square Method":
(x - h)^2 - k = 0, the vertex is (h, -k)
Complete the square:
x^2 + 2x + 1 = 0
x^2 + 2x = -1
(2/2)^2 = 1, add 1 to both sides of the equation.
x^2 + 2x + 1 = -1 + 1
(x + 1)^2 = 0
(x + 1)^2 - 0 = 0 (Just to put a placeholder in for he -k)
The vertex is (1, 0)