Answer:
0.927
Explanation:
The value can be estimated using the binomial theorem for expanding numbers. The theorem states:
For an expansion
![(1+x)^(n) = 1+ (n)/(1)x+(n(n-1))/(1*2) x^(2) + ...](https://img.qammunity.org/2020/formulas/mathematics/middle-school/77yva4x3c8oihnbzbta6ealmqa578vabei.png)
Now, let's take the value 0.6289731. In the expression, let 0.6289731 be equal to
![( 1 - 0.0371)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ikj40ln61aizylp1l0mfa7r9kyjuthryge.png)
We can use the binomial expansion above:
up to three terms
This gives 1-0.0734+0.00137641 = 0.927 up to 3 decimal places