Question

Solve the following percentages
​

Answer 1

1. £ 253,628.16

2. £ 350

3. 600,000 tickets

Explanation:

1.

We will use compound growth formula for this, the formula is:

`F=P(1+r)^t`

Where

F is future amount (what we want to find after 2 yrs)

P is present amount (240,000)

r is the rate of increase (2.8% = 2.8/100 = 0.028)

t is the time in years (t = 2 given)

Substituting, we get our answer:

`F=P(1+r)^t\\F=240,000(1+0.028)^2\\F=240,000(1.028)^2F=253,628.16`

The house would be worth £253,628.16 after 2 years

2.

After the discount of 15%, he paid 297.50. So we can say:

What number, discounted by 15%, makes 297.50?

We can let that original price be "x" and write the equation as:

`x-0.15x=297.50\\0.85x=297.50\\x=(297.50)/(0.85)\\x=350`

Originally, the laptop was worth £ 350

3.

480,000 is 80% of the total number of tickets.

If we let total number of tickets be t, we can say:

480,000 is 80% (80/100 = 0.8) of WHAT NUMBER (t)??

Now, we can write an algebraic equation and solve:

`480,000=0.8t\\t=(480,000)/(0.8)\\t=600,000`

The total number of tickets available was 600,000 tickets