Question

Help with my math please please Thank you! :)

Answer 1

Cos=square root of 11/ 6

Answer 2

cosФ =
`(√(11) )/(6)`

Explanation:

Given as Sin Ф =
`(5)/(6)`

And According to Pythagorean identity ,

sin²Ф + cos²Ф = 1

I,e cos²Ф = 1 - sin²Ф

Or, cosФ = √(1 - sin²Ф )

∵ sinФ =
`(5)/(6)`

So , cosФ =
`\sqrt{1 - ((5)/(6))^(2)}`

Or , cosФ =
`\sqrt{( 1 - ((25)/(36))`

Or, cosФ =
`\sqrt{((36-25))/(36) }`

Or, cosФ =
`(√(11) )/(6)` Answer