Question

Please help me answer for 29, 30, 31 please

Answer 1

29.
`f(10) = 0.0078`

30.
`f(5)=40.5`

31.
`f(2)=6`

Explanation:

Question 29:

Given:

`f(n)=4* ((1)/(2))^(n-1)`

Plug in 10 for n. This gives,

`f(10)=4* ((1)/(2))^(10-1)\\f(10)=4* ((1)/(2))^(9)=0.0078`

Therefore, the tenth term is 0.0078.

Question 30:

Given:

`f(n)=(1)/(2)* 3^(n-1)`

Plug in 5 for n. This gives,

`f(5)=(1)/(2)* 3^(5-1)=(1)/(2)* 3^4=(1)/(2)* 81=40.5`

Therefore, the fifth term is 40.5.

Question 31:

Given:

`f(1)=2, f(n)=f(n-1)+4`

Plug in 2 for n. This gives,

`f(2)=f(1) + 4\\f(2)=2+4=6`

Therefore, the second term is 6.