Question

Sodium hydroxide, NaoH , is a strong base that is used im industrial synthesis and processes such as making paper. What is the mass of 2.90*10^22

Answer 1

1.926 g of NaOH

Step-by-step explanation:

Concept tested: Mole and Avogadro's number

• We need to know that , 1 mole of a compound contains number of molecules equivalent to the Avogadro's number.

• Th Avogadro's number is 6.022 × 10^23

Therefore;

• 1 mole of a compound = 6.022 × 10^23 molecules

In this case; Our compound is NaOH

Therefore;

1 mole of NaOH contains 6.022 × 10^23 molecules

But; Molar mass of NaOH is 40.0 g/mol

Therefore;

• 40.0 g of NaOH contains 6.022 × 10^23 molecules

With this we can calculate the mass of 2.90 × 10^22 molecules

• Mass of a compound = (number of molecules ÷ Avogadro's constant) × molar mass

Therefore;

Mass of NaOH =(2.90 × 10^22 molecules ÷ 6.022 × 10^23 molecules)40g

= 1.9263 g

= 1.926 g NaOH

Thus, the mass of NaOH is 1.926 g