Final answer:
Aqueous ammonium bromide and lead(II) acetate do not react to form a precipitate, thus no net chemical reaction occurs and the substances remain dissolved.
Pb(NO3)2(aq) + 2NaCl(aq) → 2NaNO3(aq) + PbCl2(s).
Step-by-step explanation:
When aqueous solutions of ammonium bromide, NH4Br, and lead(II) acetate, Pb(C2H3O2)2, are mixed together, a double displacement reaction can occur. However, since both reactants are soluble and do not form an insoluble product or a precipitate in this specific combination, no net reaction will take place. The final molecular equation suggests that there are no changes on both sides of the equation. Therefore, the correct representation would be NH4Br(aq) + Pb(C2H3O2)2(aq) → No Reaction.
However, it is important to note that in a double displacement reaction that does proceed, such as when lead(II) nitrate reacts with sodium chloride to produce soluble sodium nitrate and a precipitate of lead(II) chloride, the balanced molecular equation would be Pb(NO3)2(aq) + 2NaCl(aq) → 2NaNO3(aq) + PbCl2(s).