Answer:30.7 mg of Magnesium
Explanation: The equation of reaction is;
Mg(s) + 2HCl(aq) ----> MgCl2(aq) + H2(g).
I mol of Magnessium produces 1 mol of Hydrogen gas.
Pressure,p= 754 torr, volume, v= 31.2 ml( which is also equals to 0.0312L) , R= 62.36367L torr/kmol, temperature, T = 25 + 273.15)
Step 1: find the number of moles using PV = nRT.
Making n(number of mole) the subject of the formula, we have;
n = PV/RT
Substitute the above parameters into the formula, we have;
n= (754 Torr) x (0.0312 L) / ((62.36367 L torr/K mol) x (25.0 + 273.15) K) = 0.001265 mol of Hydrogen gas.
Step 2: using n = mass/molar mass.
Mass = n × molar mass
(0.001265 mol of H2) x (1 mol Mg / 1 mol H2) x (24.30506 g Mg/mol) = 0.030745 g = 30.7 mg of Magnessium