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4 votes
Find the value of Q in the following system so that the solution to the system

is {(x,y) : x – 3y = 4}
x-3y=4
2x + Qu=8

User Nowaker
by
5.3k points

2 Answers

4 votes

Answer:

q=8/u -2x/u that is the answer

User Rob Golding
by
5.5k points
3 votes

Answer:

The value of Q is -6 for the given equations.

Explanation:

From the given question,

X - 3y = 4 equation (1)

2X + Qy = 8 equation (2)

Multiply the entire equation (1) by 2 and equation (2) by -1

Therefore equation (1) and equation (2) becomes as follows

2X - 6y = 8 equation (1)

-2X - Qy = -8 equation (2)

Add equation 1 and 2 to find Q

-6Y - Qy = 0

-Qy = 6y

Cancelling both the in L.H.S and R.H.S, we get

Q = -6

Thus we solved both the equations and found Q = -6.

User Giorgiline
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5.0k points