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Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of "84" m3/min and exits at 12 bar, 400 K. Heat transfer occurs at a rate of 14 kW from the compressor to its surroundings. Assuming the ideal gas model for air and neglecting kinetic and potential energy effects, determine the power input, in kW.

User YAHsaves
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1 Answer

5 votes

Answer:

W = - 184.8 kW

Step-by-step explanation:

Given data:


P_1 = 1.05 bar


T_1 = 300K


\dot V_1 = 84 m^3/min


P_2 = 12 bar


T_2 = 400 K

We know that work is done as


W = - [ Q + \dor m[h_2 - h_1]]

for
P_1 = 1.05 bar,  T_1 = 300K

density of air is 1.22 kg/m^3 and
h_1 = 300 kJ/kg

for
P_2 = 12 bar, T_2 = 400 K


h_2 = 400 kj/kg


\dot m = \rho * \dor v_1 = 1.22 (84)/(60) =1.708 kg/s

W = -[14 + 1.708[400-300]]

W = - 184.8 kW

User Etienne Neveu
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