Answer:
μ=0.16
Step-by-step explanation:
Given that
m= 3.5 Kg
d= 0.78 m
F= 26 N
v= 1.68 m/s
Lets take coefficient of kinetic friction = μ
Friction force Fr=μ m g
Lets take acceleration of block is a m/s²
F- Fr = m a
26 - μ x 3.5 x 10 = 3.5 a ( take g =10 m/s²)
a= 7.42 - 35μ m/s²
The final speed of the block is v
v= 1.68 m/s
We know that
v²= u²+ 2 a d
u= 0 m/s given that
1.68² = 2 x a x 0.78
a= 1.80 m/s²
a= 7.42 - 35μ m/s²
7.42 - 35μ = 1.80
μ=0.16