Question

In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, but it is larger and softer. In one hit, the ball leaves the bat at 12m/s after being in contact with the bat for 2.0ms . Assume constant acceleration during the hit.

A. What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units. a =
b. What is the net force on the ball during the hit?
Express your answer to two significant figures and include the appropriate units.
F =

Answer 1

Step-by-step explanation:

It is given that,

Mass of the ball, m = 140 g = 0.14 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 12 m/s

Time of contact,
`t=2\ ms=2* 10^(-3)\ s`

(a) Let a is the acceleration of the ball. It is equal to the rate of change of velocity. It is given by :

`a=(v-u)/(t)`

`a=(12-0)/(2* 10^(-3))`

`a=6000\ m/s^2`

(b) Let F is the net force on the ball during the hit. It is equal to the product of mass and acceleration. It is given by :

`F=ma`

`F=0.14\ kg* 6000\ m/s^2`

F = 840 N

Hence, this is the required solution.