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Two fun-loving otters are sliding toward each other on a muddy (and hence frictionless) horizontal surface. One of them, of mass 8.50 kg , is sliding to the left at 6.00 m/s, while the other, of mass 5.35 kg , is slipping to the right at 6.00 m/s. They hold fast to each other after they collide. Part A Find the magnitude of the velocity of these free-spirited otters right after they collide. | AEO o a ? m/s

User Raeisi
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1 Answer

1 vote

Answer:

v = -1.36 m/s

Step-by-step explanation:

It is given that,

Mass of object 1,
m_1=8.5\ kg

Speed of mass 1,
v_1=-6\ kg (left)

Mass of object 2,
m_2=5.35\ kg

Speed of mass 2,
v_2=6\ kg (right)

It is the case of inelastic collision. Let v is the final speed of both objects after the collision. Using the conservation of momentum as :


v=(m_1v_1+m_2v_2)/(m_1+m_2)


v=(8.5* (-6)+5.35* 6)/(8.5+5.35)

v = -1.36 m/s

So, the velocity of these free-spirited otters is 1.36 m/s towards left. Hence, this is the required solution.

User PeterBelm
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