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ABC has A(-3,6),B(2,1),and C(9,5) as its vertices the length of side AB is units . The length of side BC is ?units . The length of side AC is ? Units .ABC ?

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Answer:

The length of side AB is
√(50) units.

The length of side BC is
√(65) units.

The length of side AC is
√(145) units.

Explanation:

To find the length of each side, we use the formula for the distance between two points.

Distance between two points:

Points
(x_1,y_1) and
(x_2,y_2). The distance between them is given by:


D = √((x_2-x_1)^2+(y_2-y_1)^2)

Side AB:

Points
A(-3,6),B(2,1). So the distance between them is:


D = √((2-(-3))^2 + (1-6)^2) = √(50)

The length of side AB is
√(50) units.

Side BC:

Points
C(9,5),B(2,1). So the distance between them is:


D = √((2-9)^2 + (1-5)^2) = √(65)

The length of side BC is
√(65) units.

Side AC:

Points
A(-3,6),C(9,5). So the distance between them is:


D = √((9-(-3))^2 + (5-6)^2) = √(145)

The length of side AC is
√(145) units.

User Tim Wilder
by
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