Answer:
The tension in the part of the cord attached to the textbook is 6.58 N.
Step-by-step explanation:
Given that,
Mass of textbook = 2.09 kg
Diameter = 0.190 m
Mass of hanging book = 3.08 kg
Distance = 1.26 m
Time interval = 0.800 s
Suppose,we need to calculate the tension in the part of the cord attached to the textbook
We need to calculate the acceleration
Using equation of motion


Put the value into the formula


We need to calculate the tension
When the book is moving with acceleration
Using formula of tension



Hence, The tension in the part of the cord attached to the textbook is 6.58 N.