Question

Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) + H 2O (l) → Ca(OH) 2 (s) In a particular experiment, a 2.00-g sample of CaO is reacted with excess water and 2.14 g of Ca(OH) 2 is recovered. What is the percent yield in this experiment?

Answer 1

The answer to your question is: 81%

Step-by-step explanation:

Data

CaO = 2 g

Ca(OH)₂ = 2.14 g

Reaction balanced

CaO + H₂O ⇒ Ca(OH)₂

Molecular mass

Calcium oxyde = 40 + 16 = 56 g

Calcium hydroxide = 40 + 2 + 32 = 74 g

Process

Rule of three

56 g of CaO -------------- 74 g of Ca(OH)₂

2 g of CaO ------------- x

x = (2 x 74) / 56

x = 2.64 g of Ca(OH)₂

Percent yield

% Yield =
`(2.14)/(2.64)  x 100`

% yield = 81