Answer:
Explanation:
1) (i) HG ≅ ST ; GI ≅ TR ; IH ≅ RS
ΔHGI ≅ ΔSTR by S S S congruent
(ii) ∠H ≅ ∠S ; HG ≅ ST ; ∠G ≅ ∠T
ΔHGI ≅ ΔSTR by A S A -> Angle Side Angle congruent.
3) LM ≅ XY ; MK ≅ YZ ; KL ≅ ZX
ΔLMK ≅ ΔXYZ Side Side Side congruent
∠K ≅ ∠Z ; KL ≅ ZX ; ∠L ≅ ∠X
ΔLMK ≅ ΔXYZ by Angle Side Angle congruent