Question

Beth, a construction worker, attempts to pull a stake out of the ground by pulling on a rope that is attached to the stake. The rope makes an angle of 69.1 ◦ with the horizontal. If Beth exerts a force of 147.3 N on the rope, what is the magnitude of the upward component of the force acting on the stake?

Answer 1

`F_y=137.61N`

Step-by-step explanation:

The force exerted by Beth, has components on the two axes of the xy plane,
`Fcos\theta` on the x axis and
`Fsin\theta` on the y axis, where
`\theta` is the angle formed by the rope with the horizontal and
`F` is the magnitude of the force. So, the magnitude of the upward component of the force acting on the stake, is the force component in the y axis:

`F_y=(147.3N)sin(69.1^\circ)\\F_y=137.61N`