Question

A plane has a takeoff speed of 89.3m/s and requires 1465m to reach that speed determine the acceleration of the plane and the time required to reach this speed

Answer 1

a = 2.72 ms⁻²

32.83 s

Step-by-step explanation:

By using the kinematic equations you get,

v² = u² +2as and v = u + at where all terms in usual meaning

Using 1st equation,

89.3² = 0² + 2a×1465 ⇒ a = 2.72 ms⁻²

By 2nd equation,

89.3 = 0 + 2.72×t ⇒ t = 32.83 s