Question

Astronauts aboard the U.S.S. Burger decide to fire the rocket thrusters for 3.0 seconds to make a course correction. While the thrusters are on, the ship moves a total distance of 10,500 kilometers and increases its speed by 340 meters / sec. What is the U.S.S. Burger’s Δ V, (where V stands for speed) in meters / second?

Answer 1

340 m/s

Solution:

As per the question;

Time, t = 3.0 s

Total distance moved by the ship, d = 10,500 km

The increase in speed, v = 340 m/s

Now,

To calculate the U.S.S Burger's change in speed,
`\Delta V`:

The final velocity is given by:

`v_(f) = 340 + v_(i)` (1)

where

`v_(f) = final\ velocity`

`v_(i) = initial\ velocity`

Also, the change in velocity is given by:

`\Delta v = v_(f) - v_(i)` (2)

Now, from eqn (1) and (2):

`\Delta = 340 + v_(i) - v_(i) = 340\ m/s`