5.2k views
5 votes
You've experienced convection cooling if you've ever extended your hand out the window of a moving vehicle or into a flowing water stream. With the surface of your hand at a temperature of 30 degree C. determine the convection heat flux for a vehicle speed of 35 km/h in air at -5 degree C with a convection coefficient of 40 W/m2 . K and a velocity of 0.2 m/s in a water stream at 10 degree C with a convection coefficient of 900 W/m2 K. Which condition would feel colder? Contrast these results with a heat loss of approximately 30 W/m2 under normal room conditions.

User Vfle
by
6.8k points

1 Answer

2 votes

The Newton's law of cooling can determine the convection heat flux for the air stream. That is,


Q_A = h(T_s-T_(\infty))

Our values are,


h=40W/m^2K


T_s = 30\°c


T_(\infty) = -5\°c

A) Substituting the values in our equation,


Q_A = (40)(30-(-5))


Q_A = 1400W/m^2

Therefore the convection heat flux for the air stream is
Q_A = 1400W/m^2

B) The convection heat flux for the water can also be determined by Newton's law of cooling, i.e,


Q_W = h (T_s - T_(\infty))

Our values here are,


h= 900W/m^2K


T_s=30\°c


T_(\infty)=10°c

Substituting the values in our equation,


Q_W = (900)(30-10)


Q_W = 18000W/m^2

Therefore the connection heat flux for the water stream is 18000W/m^2

The hand feels colder in water stream when compared to air stream and uncomfortable in both the water and aire stream when compared to the hand in normal room condition

User Debajyoti Roy
by
6.6k points