Answer:
The coordinates of the circumcenter of this triangle are (3,2)
Explanation:
we know that
The circumcenter is the point where the perpendicular bisectors of a triangle intersect
we have the coordinates
![A(-2,5),B(-2,-1),C(8,-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ujz4inxu7l9evp93kmjy6tyvz2n90umuzt.png)
step 1
Find the midpoint AB
The formula to calculate the midpoint between two points is equal to
![M=((x1+x2)/(2),(y1+y2)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2ffl0lwkrr8bwtthxkz7gv940h0v5ownp1.png)
substitute the values
![M=((-2-2)/(2),(5-1)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hsg1lxbmel1kb8z8281nx23ir51dytpfc5.png)
![M_A_B=(-2,2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cliqgjtgqyyyiflxr95rtc375hiqykauog.png)
step 2
Find the equation of the line perpendicular to the segment AB that passes through the point (-2,2)
Is a horizontal line (parallel to the x-axis)
-----> equation A
step 3
Find the midpoint BC
The formula to calculate the midpoint between two points is equal to
![M=((x1+x2)/(2),(y1+y2)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2ffl0lwkrr8bwtthxkz7gv940h0v5ownp1.png)
substitute the values
![M=((-2+8)/(2),(-1-1)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9xhqdamz43hkwt65nzk57pp837rs8o8p1f.png)
![M_B_C=(3,-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6u4jbnzn9h8jj5pf6aid7szzvhcozjuqzd.png)
step 4
Find the equation of the line perpendicular to the segment BC that passes through the point (3,-1)
Is a vertical line (parallel to the y-axis)
-----> equation B
step 5
Find the circumcenter
The circumcenter is the intersection point between the equation A and equation B
-----> equation A
-----> equation B
The intersection point is (3,2)
therefore
The coordinates of the circumcenter of this triangle are (3,2)