Answer:
![p_(f)=99x10^6 N*s](https://img.qammunity.org/2020/formulas/physics/college/du2v920fnbdj9lan2myesq3n4jvcf4xv05.png)
Step-by-step explanation:
When a force is applied to an object over a certain period of time, it is said to apply an impulse to the object. The magnitude of the impulse is given by:
J=F*Δt
When an impulse is provided to an object, the momentum of the object will change, as in:
J=Δp=
![p_(f)-p_(i)](https://img.qammunity.org/2020/formulas/physics/college/odp81echt4mkpae29lrwzbfwxjtxmzaoqh.png)
So given:
Initial momentum
![P_(i)=5.19x10^7 (kg*m)/(s)](https://img.qammunity.org/2020/formulas/physics/college/l3vvlo1tzyy9p6enyuj3s9t9jkh8wmcm8n.png)
Applied force
![F=2.0x10^6 N](https://img.qammunity.org/2020/formulas/physics/college/k44g6qrw9lveokv7f654nv7kjex5czwq0y.png)
J=
![p_(f)-p_(i)](https://img.qammunity.org/2020/formulas/physics/college/odp81echt4mkpae29lrwzbfwxjtxmzaoqh.png)
F*Δt=
![p_(f)-p_(i)](https://img.qammunity.org/2020/formulas/physics/college/odp81echt4mkpae29lrwzbfwxjtxmzaoqh.png)
![p_(f)=2.0x10^6N*12s+7.5x10^7 N*s](https://img.qammunity.org/2020/formulas/physics/college/ux4c5n4gtsuhq8wocz23wwxpc65eumg5rx.png)
![p_(f)=99x10^6 N*s](https://img.qammunity.org/2020/formulas/physics/college/du2v920fnbdj9lan2myesq3n4jvcf4xv05.png)