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A triangular side of the Transamerica Pyramid Building in San Francisco, California, is 149 feet at its base. If the distance from a base corner of the building to its peak is 859 feet, how wide is the triangle halfway to the top.

A. 298 ft
B. 74.5 ft
C. 149 ft
D. 429.5 ft​

A triangular side of the Transamerica Pyramid Building in San Francisco, California-example-1

2 Answers

3 votes

Answer:D. 429.5 ft​

Explanation:

Divide 859 in half and you get 429 with remainder of 5.

User Nick Jonas
by
5.5k points
5 votes

Answer:

b.
74,5 ft.

Explanation:

The dimension of
149 ft.is the width, so you take half of 149 to get 74,5.

I am joyous to assist you anytime.

User DLunin
by
5.2k points