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Write an equation of the line that passes through (3, 2) and is perpendicular to the line y = 1/3x-3

1 Answer

8 votes

Answer:

y=1/3x-3

m1=1/3

from,m1m2=-1

1/3m2=-1

m2=-3

again, from

m=(y-y1)/(x-x1)

-3=(y-2)/(x-3)

y-2=-3(x-3)

y-2=-3x+9

y=-3x+9+2

y=-3x+11

User Aleksandr Petrov
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