211k views
1 vote
The marginal, or additional, gain from Kyoko's first hour of work, from 8:00 AM to 9:00 AM, is 80 problems.

The marginal gain from Kyoko's third hour of work, from 10:00 AM to 11:00 AM, is 40 problems.
Later, the teaching assistant in Kyoko's chemistry course gives her some advice. "Based on past experience," the teaching assistant says, "working on 30 problems raises a student's exam score by about the same amount as reading the textbook for 1 hour." For simplicity, assume students always cover the same number of pages during each hour they spend reading.
Given this information, in order to use her 4 hours of study time to get the best exam score possible, how many hours should she have spent working on problems, and how many should she have spent reading?
- 3 hours working on problems, 1 hour reading

User Malvadao
by
5.8k points

1 Answer

4 votes

Answer:

When Kyoko solves problems during 3 hours and reads for 1 hour, her learning utility is equivalent to 150 problems solved.

Step-by-step explanation:

We are not given the information about what happens between 9:00 to 10:00 AM, so we can assume that their is no marginal gain from solving problems during that hour.

Kyoko will be able to solve 120 problems (= 80 + 40) during 8:00 to 11:00 AM. Apparently she will not be able to solve any other problems beyond 11:00 AM, so in order to maximize her learning utility she must find another activity that will help her raise her test scores.

She has 1 free hour and we know that reading for 1 hour is equal to solving 30 problems, so she could decide to do that (apparently is that or doing nothing).

When Kyoko solves problems during 3 hours and reads for 1 hour, her learning utility is equivalent to 150 problems solved.

User Max Barfuss
by
5.9k points