Question

At 9:00am, a dog chased a squirrel 8 miles north. The dog gave up and stopped chasing the squirrel at 10:00am. What was the average velocity of the dog while he was chasing the squirrel?

8 mph south

16 mph north

Answer 1

16 mph north ^^

DONT HATE, if im wrong!!!!!!!! have a wonderful day~~

Answer 2

8
`(m)/(s)` was the average velocity of the dog while he was chasing the squirrel

Step-by-step explanation:

Speed ​​is a change of position of a body over time. Then the speed is defined as the amount of space traveled per unit of time with which a body travels in a certain direction and direction.

Its unit of measure in the International System (S.I.) is the meter per second (m/s)

`velocity = (distance traveled)/(time)`

In this case you know that:

• Start time = 9.00 am

• Final time = 10.00 am

Then, the change in time from 9 - 10am is 1 hour.

• Distance traveled = 8 miles north

The dog chased the squirrel for 1 hour a distance of 8 miles and you can assume that his speed was constant.

Finally:

`velocity=(distance traveled)/(time)`

`velocity=(8 miles)/(1 hour)`

`velocity= 8(m)/(s)`

8
`(m)/(s)` was the average velocity of the dog while he was chasing the squirrel