Question

PLEASE HELP

What is the pH of a solution containing a 1.0 x 10−4 M solution of HCl?

1

4

1 x 104

1 x 10−4

Answer 1

Step-by-step explanation:

In this problem, a 10 - 10 M solution of HCl contributes 10 - 10 M [H +]. The ionization of water contributes 10 - 7 M [H +].

Answer 2

4

Step-by-step explanation:

HCl ⟶ H⁺ + Cl⁻

HCl dissociates completely in solution, so

1.0 × 10⁻⁴ mol·L⁻¹ HCl ⟶ 1.0 × 10⁻⁴ mol·L⁻¹ H⁺

pH = -log(H⁺) = -log(1.0 × 10⁻⁴) = -log(1.0) - log(10⁻⁴)= -0 - log(-4) = -(-4) = 4