Question

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)?

Answer 1

A on Edge 2021

Explanation:

Answer 2

`(r)/(s)(6)=(3(6)-1)/(2(6)+1)`

Explanation:

We know that for any two function f(x) and g(x) ,

`(f)/(g)(x)=(f(x))/(g(x))`

Given functions :
`r(x)=3x-1` and
`s(x)=2x+1`

Then,
`(r)/(s)(x)=(r(x))/(s(x))`

`\Rightarrow\ (r)/(s)(x)=(3x-1)/(2x+1)`

At x= 6 , we get

`(r)/(s)(6)=(3(6)-1)/(2(6)+1)`

The , The expression is equivalent to
`(r)/(s)(6)=(3(6)-1)/(2(6)+1)`

When we further simplify it , we get
`(r)/(s)(6)=(18-1)/(12+1)=(17)/(13)`