Answer:
a) 1,332 kJ are transferred
b) the temperature of the tree decreases 1.99 ºC
Step-by-step explanation:
a) When a phase change occurs, the temperature remains constant for a pure substance, so, in this case, the heat transferred is:
Q = m*L, where m is the mass, and L is the latent heat, which for solidification of water is -333 kJ/kg:
Q = 4.00*(-333)
Q = -1332 kJ
So, 1,332 kJ are transferred.
b) If the amount of heat is transferred for the tree, and it has no phase change, it will receive a sensitive heat, which is:
Q = m*c*ΔT, where m is the mass, c is the specific heat, and ΔT the temperature change:
-1332 = 200*3.35*ΔT
670ΔT = -1332
ΔT = - 1.99 ºC
So the temperature of the tree decreases 1.99 ºC.