Question

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What is the equation of a line, in point-slope form, that passes through (-8, 1) and has a slope
of 5?
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EL
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TETET HTET
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o y+8= 5 (1-1)
O y+1= (2 – 8)
O y=8= + (x+1)
O y=1= fx+8)
On
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LLL
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Answer 1

For this case we have that by definition, the point-slope equation of a line is given by:

`y-y_ {0} = m (x-x_ {0})`

Where:

m: It's the slope

`(x_ {0}, y_ {0}):` It is a point through which the line passes

According to the statement data we have:

`m = 5\\(x_ {0}, y_ {0}): (- 8,1)`

Substituting we have:

`y-1 = 5 (x - (- 8))`

By law of signs of multiplication we have to:

`- * - = +\\y-1 = 5 (x + 8)`

Answer:

The requested equation is:
`y-1 = 5 (x + 8)`