Question

A 1430 kg car speeds up from 7.50 m/s to 11.0 m/s in 9.30 s. Ignoring friction, how much power did that require?(unit=W)PLEASE HELP

Answer 1

4980 W

Step-by-step explanation:

Power = change in energy / time

P = ΔKE / t

P = (½ mv₂² − ½ mv₁²) / t

P = ½ m (v₂² − v₁²) / t

P = ½ (1430 kg) ((11.0 m/s)² − (7.50 m/s)²) / (9.30 s)

P = 4980 W