Answer:
![h = (2A)/(b)](https://img.qammunity.org/2020/formulas/mathematics/high-school/1snczui2bbj8wsrcqja3lxwj9ce2vskg8c.png)
![h = 10~cm](https://img.qammunity.org/2020/formulas/mathematics/high-school/rrzo6bblkzsksocft1ndwuwpbzpm7eebct.png)
Explanation:
Do the first part of the problem first. Solve the area formula for the height.
Start with the area formula:
![A = (1)/(2)bh](https://img.qammunity.org/2020/formulas/mathematics/college/c7yq412tt1lqn1tss2upwekyo8oc63h720.png)
Switch sides.
![(1)/(2)bh = A](https://img.qammunity.org/2020/formulas/mathematics/high-school/phf4652vo4j34emvhwtpck5cq84d8wxibi.png)
Multiply both sides by 2.
![2 * (1)/(2)bh = 2 * A](https://img.qammunity.org/2020/formulas/mathematics/high-school/x05dok527x4ubmeyicb4s9gm77le2x6gl0.png)
![bh = 2A](https://img.qammunity.org/2020/formulas/mathematics/high-school/bfzbqqaouenai5jqme8pq5hpqh7be5wj7e.png)
Divide both sides by b.
![h = (2A)/(b)](https://img.qammunity.org/2020/formulas/mathematics/high-school/1snczui2bbj8wsrcqja3lxwj9ce2vskg8c.png)
Now that you have the formula solved for h, plug in the numbers you are given for the area and the base, and evaluate the right side to find the height.
![h = (2A)/(b)](https://img.qammunity.org/2020/formulas/mathematics/high-school/1snczui2bbj8wsrcqja3lxwj9ce2vskg8c.png)
and
![b = 9~cm](https://img.qammunity.org/2020/formulas/mathematics/high-school/2ivj3wwe9qcnejv0gpqyf7pv9xprkv4jtd.png)
![h = (2 * 45~cm^2)/(9~cm)](https://img.qammunity.org/2020/formulas/mathematics/high-school/9hk3kuk30dwam6t0molhvx8k50qdh1rznb.png)
![h = (90~cm)/(9)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ffeeed2ifvt62bqc09jv86e1wyn9ddve1n.png)
![h = 10~cm](https://img.qammunity.org/2020/formulas/mathematics/high-school/rrzo6bblkzsksocft1ndwuwpbzpm7eebct.png)