Answer:
![\angle a \textrm{ and }\angle d; \angle b \textrm{ and }\angle c](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k83rvincrxg2mvkho21yztnvtcekphhbxf.png)
Explanation:
Given:
The triangles are drawn below.
The triangles ABC and DEF are similar.
So, corresponding sides are proportional.
Here,
![(AB)/(DE)=(6)/(3)=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mgv88btgw7ooone0ot8yfgyawtvjj3111f.png)
![(BC)/(DF)=(8)/(4)=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vi426qlr9wp8e0zgrupqtwnlu17ge5dr7x.png)
![(AC)/(EF)=(4)/(2)=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qygqbzvpf2xnqvw8uyh0psy2rxi9jzjw1n.png)
Therefore,
![(AB)/(DE)=(BC)/(DF)=(AC)/(EF)=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r4zy8mfs35cqgmomgzecn4qtku20co62h3.png)
For similar triangles, the angles opposite corresponding sides are congruent and are called corresponding angles.
So, from the triangle, as sides AB and DE are corresponding sides, therefore, angles b and c are corresponding angles as they are opposite to sides AB and DE respectively.
Similarly, angles opposite to corresponding sides AC and EF are angles a and d respectively. So, angles a and d are corresponding angles.
Therefore, two sets of angles that are corresponding angles are: